Base | Representation |
---|---|
bin | 110110110011100110111101… |
… | …110000110010000010110011 |
3 | 1011121110022001202012012010211 |
4 | 312303212331300302002303 |
5 | 223043204024041104111 |
6 | 2212352420540404551 |
7 | 101525432520414565 |
oct | 6663467560620263 |
9 | 1147408052165124 |
10 | 241041043300531 |
11 | 6a891a2901a4a1 |
12 | 2304b451846757 |
13 | a4660c4092806 |
14 | 437463d4d3335 |
15 | 1cd006d8e0521 |
hex | db39bdc320b3 |
241041043300531 has 2 divisors, whose sum is σ = 241041043300532. Its totient is φ = 241041043300530.
The previous prime is 241041043300517. The next prime is 241041043300609. The reversal of 241041043300531 is 135003340140142.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 241041043300531 - 221 = 241041041203379 is a prime.
It is a super-2 number, since 2×2410410433005312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 241041043300493 and 241041043300502.
It is not a weakly prime, because it can be changed into another prime (241041043000531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120520521650265 + 120520521650266.
It is an arithmetic number, because the mean of its divisors is an integer number (120520521650266).
Almost surely, 2241041043300531 is an apocalyptic number.
241041043300531 is a deficient number, since it is larger than the sum of its proper divisors (1).
241041043300531 is an equidigital number, since it uses as much as digits as its factorization.
241041043300531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 241041043300531 its reverse (135003340140142), we get a palindrome (376044383440673).
The spelling of 241041043300531 in words is "two hundred forty-one trillion, forty-one billion, forty-three million, three hundred thousand, five hundred thirty-one".
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