Base | Representation |
---|---|
bin | 110110110011100111001101… |
… | …111110110100000100111011 |
3 | 1011121110022202201020000002201 |
4 | 312303213031332310010323 |
5 | 223043210103221224311 |
6 | 2212352503541011031 |
7 | 101525442333351355 |
oct | 6663471576640473 |
9 | 1147408681200081 |
10 | 241041315414331 |
11 | 6a892058687633 |
12 | 2304b5089b3a77 |
13 | a4661385787b3 |
14 | 43746676c80d5 |
15 | 1cd00877419c1 |
hex | db39cdfb413b |
241041315414331 has 2 divisors, whose sum is σ = 241041315414332. Its totient is φ = 241041315414330.
The previous prime is 241041315414301. The next prime is 241041315414377. The reversal of 241041315414331 is 133414513140142.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 241041315414331 - 27 = 241041315414203 is a prime.
It is a super-2 number, since 2×2410413154143312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (241041315414301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120520657707165 + 120520657707166.
It is an arithmetic number, because the mean of its divisors is an integer number (120520657707166).
Almost surely, 2241041315414331 is an apocalyptic number.
241041315414331 is a deficient number, since it is larger than the sum of its proper divisors (1).
241041315414331 is an equidigital number, since it uses as much as digits as its factorization.
241041315414331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 37.
Adding to 241041315414331 its reverse (133414513140142), we get a palindrome (374455828554473).
The spelling of 241041315414331 in words is "two hundred forty-one trillion, forty-one billion, three hundred fifteen million, four hundred fourteen thousand, three hundred thirty-one".
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