Base | Representation |
---|---|
bin | 110110110100101001000011… |
… | …111000111100110110110101 |
3 | 1011121201002020202022210200011 |
4 | 312310221003320330312311 |
5 | 223100334400321100103 |
6 | 2212445155113020221 |
7 | 101533524311441032 |
oct | 6664510370746665 |
9 | 1147632222283604 |
10 | 241112013065653 |
11 | 6a90a037664444 |
12 | 230611593b4671 |
13 | a46c9c43bc482 |
14 | 4377c52c26389 |
15 | 1cd1d2420dd6d |
hex | db4a43e3cdb5 |
241112013065653 has 32 divisors (see below), whose sum is σ = 246099688902144. Its totient is φ = 236193433422912.
The previous prime is 241112013065611. The next prime is 241112013065687. The reversal of 241112013065653 is 356560310211142.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241112013065653 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (241112013065953) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2808712750 + ... + 2808798592.
It is an arithmetic number, because the mean of its divisors is an integer number (7690615278192).
Almost surely, 2241112013065653 is an apocalyptic number.
It is an amenable number.
241112013065653 is a deficient number, since it is larger than the sum of its proper divisors (4987675836491).
241112013065653 is a wasteful number, since it uses less digits than its factorization.
241112013065653 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86961.
The product of its (nonzero) digits is 129600, while the sum is 40.
Adding to 241112013065653 its reverse (356560310211142), we get a palindrome (597672323276795).
The spelling of 241112013065653 in words is "two hundred forty-one trillion, one hundred twelve billion, thirteen million, sixty-five thousand, six hundred fifty-three".
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