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24113130000 = 243541674813
BaseRepresentation
bin10110011101010000…
…010010101000010000
32022020111002220212220
4112131100102220100
5343340430130000
615024420021040
71512355136361
oct263520225020
968214086786
1024113130000
11a254262513
12480b531780
13237388927b
14124a687b68
15961ddb1a0
hex59d412a10

24113130000 has 200 divisors, whose sum is σ = 78322778688. Its totient is φ = 6390336000.

The previous prime is 24113129959. The next prime is 24113130049. The reversal of 24113130000 is 3131142.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 5007594 + ... + 5012406.

Almost surely, 224113130000 is an apocalyptic number.

24113130000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 24113130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (39161389344).

24113130000 is an abundant number, since it is smaller than the sum of its proper divisors (54209648688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

24113130000 is a wasteful number, since it uses less digits than its factorization.

24113130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5011 (or 4990 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 24113130000 its reverse (3131142), we get a palindrome (24116261142).

The spelling of 24113130000 in words is "twenty-four billion, one hundred thirteen million, one hundred thirty thousand".