Base | Representation |
---|---|
bin | 110110110100111100111010… |
… | …101010111110000100100011 |
3 | 1011121210010021120222222121121 |
4 | 312310330322222332010203 |
5 | 223101212031302222042 |
6 | 2212503042442233111 |
7 | 101535210534111013 |
oct | 6664747252760443 |
9 | 1147703246888547 |
10 | 241133333242147 |
11 | 6a918088311615 |
12 | 230653094b5797 |
13 | a471a11447918 |
14 | 4378cb65a1c43 |
15 | 1cd2670d03367 |
hex | db4f3aabe123 |
241133333242147 has 2 divisors, whose sum is σ = 241133333242148. Its totient is φ = 241133333242146.
The previous prime is 241133333242133. The next prime is 241133333242169. The reversal of 241133333242147 is 741242333331142.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 241133333242147 - 243 = 232337240219939 is a prime.
It is not a weakly prime, because it can be changed into another prime (241133333242447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120566666621073 + 120566666621074.
It is an arithmetic number, because the mean of its divisors is an integer number (120566666621074).
Almost surely, 2241133333242147 is an apocalyptic number.
241133333242147 is a deficient number, since it is larger than the sum of its proper divisors (1).
241133333242147 is an equidigital number, since it uses as much as digits as its factorization.
241133333242147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 870912, while the sum is 43.
Adding to 241133333242147 its reverse (741242333331142), we get a palindrome (982375666573289).
The spelling of 241133333242147 in words is "two hundred forty-one trillion, one hundred thirty-three billion, three hundred thirty-three million, two hundred forty-two thousand, one hundred forty-seven".
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