Base | Representation |
---|---|
bin | 100011000110101000010… |
… | …111101110010000011001 |
3 | 22112121120102202022220102 |
4 | 203012220113232100121 |
5 | 304010343132202441 |
6 | 5044110155505145 |
7 | 336166035645452 |
oct | 43065027562031 |
9 | 8477512668812 |
10 | 2412301444121 |
11 | 850062305228 |
12 | 32b62aa581b5 |
13 | 14662c61c41a |
14 | 84a826dc129 |
15 | 42b3983d69b |
hex | 231a85ee419 |
2412301444121 has 2 divisors, whose sum is σ = 2412301444122. Its totient is φ = 2412301444120.
The previous prime is 2412301444117. The next prime is 2412301444139. The reversal of 2412301444121 is 1214441032142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2257686553600 + 154614890521 = 1502560^2 + 393211^2 .
It is a cyclic number.
It is not a de Polignac number, because 2412301444121 - 22 = 2412301444117 is a prime.
It is not a weakly prime, because it can be changed into another prime (2412301444921) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206150722060 + 1206150722061.
It is an arithmetic number, because the mean of its divisors is an integer number (1206150722061).
Almost surely, 22412301444121 is an apocalyptic number.
It is an amenable number.
2412301444121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2412301444121 is an equidigital number, since it uses as much as digits as its factorization.
2412301444121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 2412301444121 its reverse (1214441032142), we get a palindrome (3626742476263).
The spelling of 2412301444121 in words is "two trillion, four hundred twelve billion, three hundred one million, four hundred forty-four thousand, one hundred twenty-one".
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