Base | Representation |
---|---|
bin | 110110110110101100101001… |
… | …010001001001100110011010 |
3 | 1011122012120221022021021001011 |
4 | 312312230221101021212122 |
5 | 223110143224342021432 |
6 | 2213034123001444134 |
7 | 101546655453501043 |
oct | 6666545121114632 |
9 | 1148176838237034 |
10 | 241253300345242 |
11 | 6a963a4a647809 |
12 | 2308460a1a064a |
13 | a48011c884563 |
14 | 4380a173c38ca |
15 | 1cd5842e5b847 |
hex | db6b2944999a |
241253300345242 has 64 divisors (see below), whose sum is σ = 386741699435520. Its totient is φ = 112597795094400.
The previous prime is 241253300345203. The next prime is 241253300345263. The reversal of 241253300345242 is 242543003352142.
241253300345242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 241253300345195 and 241253300345204.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26537593117 + ... + 26537602207.
It is an arithmetic number, because the mean of its divisors is an integer number (6042839053680).
Almost surely, 2241253300345242 is an apocalyptic number.
241253300345242 is a deficient number, since it is larger than the sum of its proper divisors (145488399090278).
241253300345242 is a wasteful number, since it uses less digits than its factorization.
241253300345242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19699.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 241253300345242 its reverse (242543003352142), we get a palindrome (483796303697384).
The spelling of 241253300345242 in words is "two hundred forty-one trillion, two hundred fifty-three billion, three hundred million, three hundred forty-five thousand, two hundred forty-two".
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