Base | Representation |
---|---|
bin | 110110110110101101101101… |
… | …010010000011110100110001 |
3 | 1011122012200212211102121010012 |
4 | 312312231231102003310301 |
5 | 223110203044001400132 |
6 | 2213034432123144305 |
7 | 101550025650546455 |
oct | 6666555522036461 |
9 | 1148180784377105 |
10 | 241254441434417 |
11 | 6a964485776a14 |
12 | 23084888375095 |
13 | a4802720c0758 |
14 | 4380ac4b7a665 |
15 | 1cd58ad20c0b2 |
hex | db6b6d483d31 |
241254441434417 has 2 divisors, whose sum is σ = 241254441434418. Its totient is φ = 241254441434416.
The previous prime is 241254441434389. The next prime is 241254441434431. The reversal of 241254441434417 is 714434144452142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 211377897623281 + 29876543811136 = 14538841^2 + 5465944^2 .
It is a cyclic number.
It is not a de Polignac number, because 241254441434417 - 214 = 241254441418033 is a prime.
It is not a weakly prime, because it can be changed into another prime (241254441436417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120627220717208 + 120627220717209.
It is an arithmetic number, because the mean of its divisors is an integer number (120627220717209).
Almost surely, 2241254441434417 is an apocalyptic number.
It is an amenable number.
241254441434417 is a deficient number, since it is larger than the sum of its proper divisors (1).
241254441434417 is an equidigital number, since it uses as much as digits as its factorization.
241254441434417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6881280, while the sum is 50.
Adding to 241254441434417 its reverse (714434144452142), we get a palindrome (955688585886559).
The spelling of 241254441434417 in words is "two hundred forty-one trillion, two hundred fifty-four billion, four hundred forty-one million, four hundred thirty-four thousand, four hundred seventeen".
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