Base | Representation |
---|---|
bin | 110110110111100001110001… |
… | …010110111100110010001011 |
3 | 1011122102001011210201111020101 |
4 | 312313201301112330302023 |
5 | 223112112041131300021 |
6 | 2213120235233510231 |
7 | 101554045201116445 |
oct | 6667416126746213 |
9 | 1148361153644211 |
10 | 241310344400011 |
11 | 6a986162514427 |
12 | 2309368a112377 |
13 | a485610ab3513 |
14 | 43836a945b495 |
15 | 1cd7080e1da91 |
hex | db78715bcc8b |
241310344400011 has 2 divisors, whose sum is σ = 241310344400012. Its totient is φ = 241310344400010.
The previous prime is 241310344399909. The next prime is 241310344400053. The reversal of 241310344400011 is 110004443013142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241310344400011 - 213 = 241310344391819 is a prime.
It is not a weakly prime, because it can be changed into another prime (241310344400611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120655172200005 + 120655172200006.
It is an arithmetic number, because the mean of its divisors is an integer number (120655172200006).
Almost surely, 2241310344400011 is an apocalyptic number.
241310344400011 is a deficient number, since it is larger than the sum of its proper divisors (1).
241310344400011 is an equidigital number, since it uses as much as digits as its factorization.
241310344400011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 241310344400011 its reverse (110004443013142), we get a palindrome (351314787413153).
The spelling of 241310344400011 in words is "two hundred forty-one trillion, three hundred ten billion, three hundred forty-four million, four hundred thousand, eleven".
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