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241310555137 is a prime number
BaseRepresentation
bin1110000010111100111…
…0101101110000000001
3212001212100101022200001
43200233032231300001
512423201000231022
6302505002400001
723301620606161
oct3405716556001
9761770338601
10241310555137
1193380576763
123a926500001
13199a8a63b42
14b97275a5a1
156425033b27
hex382f3adc01

241310555137 has 2 divisors, whose sum is σ = 241310555138. Its totient is φ = 241310555136.

The previous prime is 241310555119. The next prime is 241310555153. The reversal of 241310555137 is 731555013142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139099907521 + 102210647616 = 372961^2 + 319704^2 .

It is a cyclic number.

It is not a de Polignac number, because 241310555137 - 223 = 241302166529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 241310555096 and 241310555105.

It is not a weakly prime, because it can be changed into another prime (241310559137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120655277568 + 120655277569.

It is an arithmetic number, because the mean of its divisors is an integer number (120655277569).

Almost surely, 2241310555137 is an apocalyptic number.

It is an amenable number.

241310555137 is a deficient number, since it is larger than the sum of its proper divisors (1).

241310555137 is an equidigital number, since it uses as much as digits as its factorization.

241310555137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63000, while the sum is 37.

Adding to 241310555137 its reverse (731555013142), we get a palindrome (972865568279).

The spelling of 241310555137 in words is "two hundred forty-one billion, three hundred ten million, five hundred fifty-five thousand, one hundred thirty-seven".