Search a number
-
+
241315314331409 is a prime number
BaseRepresentation
bin110110110111100110011001…
…100101101110111100010001
31011122102112000011112011102122
4312313212121211232330101
5223112202230432101114
62213122420332424025
7101554312306621403
oct6667463145567421
91148375004464378
10241315314331409
116a98828295444a
1223094636618015
13a485c23644b26
144383a1b532b73
151cd72723d5e8e
hexdb799996ef11

241315314331409 has 2 divisors, whose sum is σ = 241315314331410. Its totient is φ = 241315314331408.

The previous prime is 241315314331381. The next prime is 241315314331439. The reversal of 241315314331409 is 904133413513142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 140158890232384 + 101156424099025 = 11838872^2 + 10057655^2 .

It is a cyclic number.

It is not a de Polignac number, because 241315314331409 - 240 = 240215802703633 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 241315314331409.

It is not a weakly prime, because it can be changed into another prime (241315314331439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120657657165704 + 120657657165705.

It is an arithmetic number, because the mean of its divisors is an integer number (120657657165705).

Almost surely, 2241315314331409 is an apocalyptic number.

It is an amenable number.

241315314331409 is a deficient number, since it is larger than the sum of its proper divisors (1).

241315314331409 is an equidigital number, since it uses as much as digits as its factorization.

241315314331409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 44.

The spelling of 241315314331409 in words is "two hundred forty-one trillion, three hundred fifteen billion, three hundred fourteen million, three hundred thirty-one thousand, four hundred nine".