Base | Representation |
---|---|
bin | 100011000111100000010… |
… | …101010000111111010011 |
3 | 22112200222212102101001011 |
4 | 203013200111100333103 |
5 | 304014304010332201 |
6 | 5044343255151351 |
7 | 336231226205644 |
oct | 43074025207723 |
9 | 8480885371034 |
10 | 2413240324051 |
11 | 8504a4282657 |
12 | 32b851375557 |
13 | 14674bca988b |
14 | 84b312996cb |
15 | 42b91e9a151 |
hex | 231e0550fd3 |
2413240324051 has 2 divisors, whose sum is σ = 2413240324052. Its totient is φ = 2413240324050.
The previous prime is 2413240324039. The next prime is 2413240324067. The reversal of 2413240324051 is 1504230423142.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2413240324051 - 221 = 2413238226899 is a prime.
It is a super-3 number, since 3×24132403240513 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2413240324021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206620162025 + 1206620162026.
It is an arithmetic number, because the mean of its divisors is an integer number (1206620162026).
Almost surely, 22413240324051 is an apocalyptic number.
2413240324051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2413240324051 is an equidigital number, since it uses as much as digits as its factorization.
2413240324051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 2413240324051 its reverse (1504230423142), we get a palindrome (3917470747193).
Subtracting from 2413240324051 its reverse (1504230423142), we obtain a palindrome (909009900909).
The spelling of 2413240324051 in words is "two trillion, four hundred thirteen billion, two hundred forty million, three hundred twenty-four thousand, fifty-one".
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