Base | Representation |
---|---|
bin | 110110110111101111101110… |
… | …000110100000000101110011 |
3 | 1011122110110211121222121202122 |
4 | 312313233232012200011303 |
5 | 223112333224432021232 |
6 | 2213131153354504455 |
7 | 101555115310614062 |
oct | 6667575606400563 |
9 | 1148413747877678 |
10 | 241325322142067 |
11 | 6a991549013749 |
12 | 2309656a13512b |
13 | a486b59b38497 |
14 | 43842ca72a1d9 |
15 | 1cd765acd8312 |
hex | db7bee1a0173 |
241325322142067 has 2 divisors, whose sum is σ = 241325322142068. Its totient is φ = 241325322142066.
The previous prime is 241325322142001. The next prime is 241325322142097. The reversal of 241325322142067 is 760241223523142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241325322142067 - 28 = 241325322141811 is a prime.
It is a super-2 number, since 2×2413253221420672 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (241325322142097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120662661071033 + 120662661071034.
It is an arithmetic number, because the mean of its divisors is an integer number (120662661071034).
Almost surely, 2241325322142067 is an apocalyptic number.
241325322142067 is a deficient number, since it is larger than the sum of its proper divisors (1).
241325322142067 is an equidigital number, since it uses as much as digits as its factorization.
241325322142067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 967680, while the sum is 44.
The spelling of 241325322142067 in words is "two hundred forty-one trillion, three hundred twenty-five billion, three hundred twenty-two million, one hundred forty-two thousand, sixty-seven".
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