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241331200142017 is a prime number
BaseRepresentation
bin110110110111110101001100…
…011101010010101011000001
31011122111001000021110221211111
4312313311030131102223001
5223112432244214021032
62213134004532443321
7101555414054031136
oct6667651435225301
91148431007427744
10241331200142017
116a993a94a97047
122309772a779541
13a487585859b6b
1443846c725c58d
151cd78a1d72c47
hexdb7d4c752ac1

241331200142017 has 2 divisors, whose sum is σ = 241331200142018. Its totient is φ = 241331200142016.

The previous prime is 241331200141981. The next prime is 241331200142069. The reversal of 241331200142017 is 710241002133142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 183095971439616 + 58235228702401 = 13531296^2 + 7631201^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-241331200142017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 241331200142017.

It is not a weakly prime, because it can be changed into another prime (241331207142017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120665600071008 + 120665600071009.

It is an arithmetic number, because the mean of its divisors is an integer number (120665600071009).

Almost surely, 2241331200142017 is an apocalyptic number.

It is an amenable number.

241331200142017 is a deficient number, since it is larger than the sum of its proper divisors (1).

241331200142017 is an equidigital number, since it uses as much as digits as its factorization.

241331200142017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 241331200142017 its reverse (710241002133142), we get a palindrome (951572202275159).

The spelling of 241331200142017 in words is "two hundred forty-one trillion, three hundred thirty-one billion, two hundred million, one hundred forty-two thousand, seventeen".