Base | Representation |
---|---|
bin | 1110000011000010000… |
… | …1110010101001001011 |
3 | 212001220212100202110102 |
4 | 3200300201302221023 |
5 | 12423222034130011 |
6 | 302511101240015 |
7 | 23302303661651 |
oct | 3406041625113 |
9 | 761825322412 |
10 | 241332333131 |
11 | 933918a08aa |
12 | 3a93186300b |
13 | 199b041a626 |
14 | b9755c8dd1 |
15 | 6426dd673b |
hex | 3830872a4b |
241332333131 has 2 divisors, whose sum is σ = 241332333132. Its totient is φ = 241332333130.
The previous prime is 241332333113. The next prime is 241332333157. The reversal of 241332333131 is 131333233142.
Together with previous prime (241332333113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241332333131 is a prime.
It is a super-2 number, since 2×2413323331312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 241332333094 and 241332333103.
It is not a weakly prime, because it can be changed into another prime (241332333631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120666166565 + 120666166566.
It is an arithmetic number, because the mean of its divisors is an integer number (120666166566).
Almost surely, 2241332333131 is an apocalyptic number.
241332333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
241332333131 is an equidigital number, since it uses as much as digits as its factorization.
241332333131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11664, while the sum is 29.
Adding to 241332333131 its reverse (131333233142), we get a palindrome (372665566273).
The spelling of 241332333131 in words is "two hundred forty-one billion, three hundred thirty-two million, three hundred thirty-three thousand, one hundred thirty-one".
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