2413420013 has 4 divisors (see below), whose sum is σ = 2413518780. Its totient is φ = 2413321248.

The previous prime is 2413420007. The next prime is 2413420019. The reversal of 2413420013 is 3100243142.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3100243142 = 2 ⋅1550121571.

It is an interprime number because it is at equal distance from previous prime (2413420007) and next prime (2413420019).

It can be written as a sum of positive squares in 2 ways, for example, as 1400780329 + 1012639684 = 37427^2 + 31822^2 .

It is a cyclic number.

It is not a de Polignac number, because 2413420013 - 2⁶ = 2413419949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2413420019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17153 + ... + 71561.

It is an arithmetic number, because the mean of its divisors is an integer number (603379695).

Almost surely, 2^2413420013 is an apocalyptic number.

It is an amenable number.

2413420013 is a deficient number, since it is larger than the sum of its proper divisors (98767).

2413420013 is an equidigital number, since it uses as much as digits as its factorization.

2413420013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98766.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 2413420013 is about 49126.5713540035. The cubic root of 2413420013 is about 1341.3567629138.

Adding to 2413420013 its reverse (3100243142), we get a palindrome (5513663155).

The spelling of 2413420013 in words is "two billion, four hundred thirteen million, four hundred twenty thousand, thirteen".