Base | Representation |
---|---|
bin | 1010111110100100010001… |
… | …11101110010001001111001 |
3 | 10011110202121002101111102112 |
4 | 11133102020331302021321 |
5 | 11131002222102213423 |
6 | 123201434104142105 |
7 | 5041026024164321 |
oct | 537221075621171 |
9 | 104422532344375 |
10 | 24140014101113 |
11 | 77677a46a4159 |
12 | 285a5b5a67935 |
13 | 106151686a8c1 |
14 | 5d6550a1a281 |
15 | 2bce0cdeaa78 |
hex | 15f488f72279 |
24140014101113 has 2 divisors, whose sum is σ = 24140014101114. Its totient is φ = 24140014101112.
The previous prime is 24140014101029. The next prime is 24140014101187. The reversal of 24140014101113 is 31110141004142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15560721205264 + 8579292895849 = 3944708^2 + 2929043^2 .
It is a cyclic number.
It is not a de Polignac number, because 24140014101113 - 220 = 24140013052537 is a prime.
It is not a weakly prime, because it can be changed into another prime (24140014106113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12070007050556 + 12070007050557.
It is an arithmetic number, because the mean of its divisors is an integer number (12070007050557).
Almost surely, 224140014101113 is an apocalyptic number.
It is an amenable number.
24140014101113 is a deficient number, since it is larger than the sum of its proper divisors (1).
24140014101113 is an equidigital number, since it uses as much as digits as its factorization.
24140014101113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 24140014101113 its reverse (31110141004142), we get a palindrome (55250155105255).
The spelling of 24140014101113 in words is "twenty-four trillion, one hundred forty billion, fourteen million, one hundred one thousand, one hundred thirteen".
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