Base | Representation |
---|---|
bin | 1010111110100100011110… |
… | …10110110010111000110101 |
3 | 10011110202212120010211110221 |
4 | 11133102033112302320311 |
5 | 11131002432024233023 |
6 | 123201452454214341 |
7 | 5041031465426635 |
oct | 537221726627065 |
9 | 104422776124427 |
10 | 24140121321013 |
11 | 776784a177045 |
12 | 285a6259543b1 |
13 | 1061532b3b729 |
14 | 5d6560d6a6c5 |
15 | 2bce1752985d |
hex | 15f48f5b2e35 |
24140121321013 has 4 divisors (see below), whose sum is σ = 24140255777440. Its totient is φ = 24139986864588.
The previous prime is 24140121321011. The next prime is 24140121321049. The reversal of 24140121321013 is 31012312104142.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 24140121321013 - 21 = 24140121321011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (24140121321011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66958545 + ... + 67318102.
It is an arithmetic number, because the mean of its divisors is an integer number (6035063944360).
Almost surely, 224140121321013 is an apocalyptic number.
It is an amenable number.
24140121321013 is a deficient number, since it is larger than the sum of its proper divisors (134456427).
24140121321013 is a wasteful number, since it uses less digits than its factorization.
24140121321013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134456426.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 24140121321013 its reverse (31012312104142), we get a palindrome (55152433425155).
The spelling of 24140121321013 in words is "twenty-four trillion, one hundred forty billion, one hundred twenty-one million, three hundred twenty-one thousand, thirteen".
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