Search a number
-
+
241412113 is a prime number
BaseRepresentation
bin11100110001110…
…10100000010001
3121211021000011101
432120322200101
5443300141423
635542144401
75660653255
oct1630724021
9554230141
10241412113
111142a8548
1268a22101
133b026807
14240c2265
15162d97ad
hexe63a811

241412113 has 2 divisors, whose sum is σ = 241412114. Its totient is φ = 241412112.

The previous prime is 241412089. The next prime is 241412131. The reversal of 241412113 is 311214142.

Together with next prime (241412131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140469904 + 100942209 = 11852^2 + 10047^2 .

It is a cyclic number.

It is not a de Polignac number, because 241412113 - 221 = 239314961 is a prime.

It is not a weakly prime, because it can be changed into another prime (241412173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120706056 + 120706057.

It is an arithmetic number, because the mean of its divisors is an integer number (120706057).

Almost surely, 2241412113 is an apocalyptic number.

It is an amenable number.

241412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

241412113 is an equidigital number, since it uses as much as digits as its factorization.

241412113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 192, while the sum is 19.

The square root of 241412113 is about 15537.4422927327. The cubic root of 241412113 is about 622.6629417061.

Adding to 241412113 its reverse (311214142), we get a palindrome (552626255).

The spelling of 241412113 in words is "two hundred forty-one million, four hundred twelve thousand, one hundred thirteen".