Base | Representation |
---|---|
bin | 110110111001001100100101… |
… | …010110000000110110111100 |
3 | 1011122211000012122221100022022 |
4 | 312321030211112000312330 |
5 | 223121001432000000012 |
6 | 2213245043520535312 |
7 | 101565245245632032 |
oct | 6671144526006674 |
9 | 1148730178840268 |
10 | 241425033203132 |
11 | 6aa1a86633a739 |
12 | 230b1957181538 |
13 | a49338a82092c |
14 | 4389069256552 |
15 | 1cda04499b472 |
hex | db9325580dbc |
241425033203132 has 6 divisors (see below), whose sum is σ = 422493808105488. Its totient is φ = 120712516601564.
The previous prime is 241425033203083. The next prime is 241425033203149. The reversal of 241425033203132 is 231302330524142.
241425033203132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 241425033203092 and 241425033203101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30178129150388 + ... + 30178129150395.
It is an arithmetic number, because the mean of its divisors is an integer number (70415634684248).
Almost surely, 2241425033203132 is an apocalyptic number.
It is an amenable number.
241425033203132 is a deficient number, since it is larger than the sum of its proper divisors (181068774902356).
241425033203132 is a wasteful number, since it uses less digits than its factorization.
241425033203132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60356258300787 (or 60356258300785 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 241425033203132 its reverse (231302330524142), we get a palindrome (472727363727274).
The spelling of 241425033203132 in words is "two hundred forty-one trillion, four hundred twenty-five billion, thirty-three million, two hundred three thousand, one hundred thirty-two".
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