Base | Representation |
---|---|
bin | 100011001000011111101… |
… | …001010001101000001001 |
3 | 22112210201220011020101001 |
4 | 203020133221101220021 |
5 | 304023442422043103 |
6 | 5045040522055001 |
7 | 336266444640256 |
oct | 43103751215011 |
9 | 8483656136331 |
10 | 2414302534153 |
11 | 850999926844 |
12 | 32baa904a461 |
13 | 14688b088973 |
14 | 84bd239c42d |
15 | 42c0536901d |
hex | 2321fa51a09 |
2414302534153 has 2 divisors, whose sum is σ = 2414302534154. Its totient is φ = 2414302534152.
The previous prime is 2414302534121. The next prime is 2414302534213. The reversal of 2414302534153 is 3514352034142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2375087841424 + 39214692729 = 1541132^2 + 198027^2 .
It is a cyclic number.
It is not a de Polignac number, because 2414302534153 - 25 = 2414302534121 is a prime.
It is not a weakly prime, because it can be changed into another prime (2414302534103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1207151267076 + 1207151267077.
It is an arithmetic number, because the mean of its divisors is an integer number (1207151267077).
Almost surely, 22414302534153 is an apocalyptic number.
It is an amenable number.
2414302534153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2414302534153 is an equidigital number, since it uses as much as digits as its factorization.
2414302534153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 2414302534153 its reverse (3514352034142), we get a palindrome (5928654568295).
The spelling of 2414302534153 in words is "two trillion, four hundred fourteen billion, three hundred two million, five hundred thirty-four thousand, one hundred fifty-three".
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