2420250433 has 4 divisors (see below), whose sum is σ = 2420625328. Its totient is φ = 2419875540.

The previous prime is 2420250409. The next prime is 2420250449. The reversal of 2420250433 is 3340520242.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3340520242 = 2 ⋅1670260121.

It is a cyclic number.

It is not a de Polignac number, because 2420250433 - 2⁹ = 2420249921 is a prime.

It is a super-2 number, since 2×2420250433² = 11715224316873374978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2420250398 and 2420250407.

It is not an unprimeable number, because it can be changed into a prime (2420250403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177591 + ... + 190732.

It is an arithmetic number, because the mean of its divisors is an integer number (605156332).

Almost surely, 2^2420250433 is an apocalyptic number.

It is an amenable number.

2420250433 is a deficient number, since it is larger than the sum of its proper divisors (374895).

2420250433 is an equidigital number, since it uses as much as digits as its factorization.

2420250433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 374894.

The product of its (nonzero) digits is 5760, while the sum is 25.

The square root of 2420250433 is about 49196.0408264730. The cubic root of 2420250433 is about 1342.6209993043.

Adding to 2420250433 its reverse (3340520242), we get a palindrome (5760770675).

The spelling of 2420250433 in words is "two billion, four hundred twenty million, two hundred fifty thousand, four hundred thirty-three".