Base | Representation |
---|---|
bin | 100011001110101111101… |
… | …100010011010101110011 |
3 | 22120110001122100220021020 |
4 | 203032233230103111303 |
5 | 304131214114322003 |
6 | 5052110520430523 |
7 | 336624663164100 |
oct | 43165754232563 |
9 | 8513048326236 |
10 | 2421014214003 |
11 | 8538234541a0 |
12 | 331260918443 |
13 | 1473ba723168 |
14 | 8526b905aa7 |
15 | 42e996ced53 |
hex | 233afb13573 |
2421014214003 has 48 divisors (see below), whose sum is σ = 4312010528640. Its totient is φ = 1191476563200.
The previous prime is 2421014213987. The next prime is 2421014214049. The reversal of 2421014214003 is 3004124101242.
It is not a de Polignac number, because 2421014214003 - 24 = 2421014213987 is a prime.
It is a super-3 number, since 3×24210142140033 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (2421014204003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 39369958 + ... + 39431403.
It is an arithmetic number, because the mean of its divisors is an integer number (89833552680).
Almost surely, 22421014214003 is an apocalyptic number.
2421014214003 is a deficient number, since it is larger than the sum of its proper divisors (1890996314637).
2421014214003 is a wasteful number, since it uses less digits than its factorization.
2421014214003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78801408 (or 78801401 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 2421014214003 its reverse (3004124101242), we get a palindrome (5425138315245).
The spelling of 2421014214003 in words is "two trillion, four hundred twenty-one billion, fourteen million, two hundred fourteen thousand, three".
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