Base | Representation |
---|---|
bin | 10110100011001001… |
… | …111010001001000011 |
3 | 2022111101101010211001 |
4 | 112203021322021003 |
5 | 344041300321011 |
6 | 15042313432431 |
7 | 1514666424343 |
oct | 264311721103 |
9 | 68441333731 |
10 | 24212120131 |
11 | a2a5124241 |
12 | 483870b717 |
13 | 238b238204 |
14 | 1259894d23 |
15 | 96a9417c1 |
hex | 5a327a243 |
24212120131 has 2 divisors, whose sum is σ = 24212120132. Its totient is φ = 24212120130.
The previous prime is 24212120117. The next prime is 24212120173. The reversal of 24212120131 is 13102121242.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 24212120131 - 25 = 24212120099 is a prime.
It is a super-2 number, since 2×242121201312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 24212120099 and 24212120108.
It is not a weakly prime, because it can be changed into another prime (24212520131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12106060065 + 12106060066.
It is an arithmetic number, because the mean of its divisors is an integer number (12106060066).
Almost surely, 224212120131 is an apocalyptic number.
24212120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
24212120131 is an equidigital number, since it uses as much as digits as its factorization.
24212120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 24212120131 its reverse (13102121242), we get a palindrome (37314241373).
The spelling of 24212120131 in words is "twenty-four billion, two hundred twelve million, one hundred twenty thousand, one hundred thirty-one".
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