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242225513352131 is a prime number
BaseRepresentation
bin110111000100110110000101…
…101011011100101111000011
31011202122112101111120011220012
4313010312011223130233003
5223222110322404232011
62215100510432335135
7102010134012632261
oct6704660553345703
91152575344504805
10242225513352131
11701a9299532491
1223200b163a44ab
13a5209ca0c1a2a
1443b5ac5287431
151d00c94ed4a8b
hexdc4d85adcbc3

242225513352131 has 2 divisors, whose sum is σ = 242225513352132. Its totient is φ = 242225513352130.

The previous prime is 242225513352113. The next prime is 242225513352139. The reversal of 242225513352131 is 131253315522242.

Together with previous prime (242225513352113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-242225513352131 is a prime.

It is a super-2 number, since 2×2422255133521312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (242225513352139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121112756676065 + 121112756676066.

It is an arithmetic number, because the mean of its divisors is an integer number (121112756676066).

Almost surely, 2242225513352131 is an apocalyptic number.

242225513352131 is a deficient number, since it is larger than the sum of its proper divisors (1).

242225513352131 is an equidigital number, since it uses as much as digits as its factorization.

242225513352131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 432000, while the sum is 41.

Adding to 242225513352131 its reverse (131253315522242), we get a palindrome (373478828874373).

The spelling of 242225513352131 in words is "two hundred forty-two trillion, two hundred twenty-five billion, five hundred thirteen million, three hundred fifty-two thousand, one hundred thirty-one".