Base | Representation |
---|---|
bin | 10110100011110111… |
… | …010001101101001011 |
3 | 2022112012202100221112 |
4 | 112203313101231023 |
5 | 344102321410011 |
6 | 15043420400535 |
7 | 1515202466663 |
oct | 264367215513 |
9 | 68465670845 |
10 | 24224013131 |
11 | a30090766a |
12 | 48406a614b |
13 | 23908405a6 |
14 | 125b2ad1a3 |
15 | 96b9e058b |
hex | 5a3dd1b4b |
24224013131 has 2 divisors, whose sum is σ = 24224013132. Its totient is φ = 24224013130.
The previous prime is 24224013127. The next prime is 24224013139. The reversal of 24224013131 is 13131042242.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 24224013131 - 22 = 24224013127 is a prime.
It is a super-2 number, since 2×242240131312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 24224013097 and 24224013106.
It is not a weakly prime, because it can be changed into another prime (24224013139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12112006565 + 12112006566.
It is an arithmetic number, because the mean of its divisors is an integer number (12112006566).
Almost surely, 224224013131 is an apocalyptic number.
24224013131 is a deficient number, since it is larger than the sum of its proper divisors (1).
24224013131 is an equidigital number, since it uses as much as digits as its factorization.
24224013131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 24224013131 its reverse (13131042242), we get a palindrome (37355055373).
The spelling of 24224013131 in words is "twenty-four billion, two hundred twenty-four million, thirteen thousand, one hundred thirty-one".
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