Base | Representation |
---|---|
bin | 1110000110101011101… |
… | …1011000101100011001 |
3 | 212011110011000010220012 |
4 | 3201222323120230121 |
5 | 12432223400333423 |
6 | 303152221411305 |
7 | 23335502021456 |
oct | 3415273305431 |
9 | 764404003805 |
10 | 242312121113 |
11 | 9384496a037 |
12 | 3ab65a09b35 |
13 | 19b083cba2a |
14 | ba2979482d |
15 | 6482e24078 |
hex | 386aed8b19 |
242312121113 has 2 divisors, whose sum is σ = 242312121114. Its totient is φ = 242312121112.
The previous prime is 242312121109. The next prime is 242312121131. The reversal of 242312121113 is 311121213242.
Together with next prime (242312121131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 241407134224 + 904986889 = 491332^2 + 30083^2 .
It is a cyclic number.
It is not a de Polignac number, because 242312121113 - 22 = 242312121109 is a prime.
It is not a weakly prime, because it can be changed into another prime (242312121133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121156060556 + 121156060557.
It is an arithmetic number, because the mean of its divisors is an integer number (121156060557).
Almost surely, 2242312121113 is an apocalyptic number.
It is an amenable number.
242312121113 is a deficient number, since it is larger than the sum of its proper divisors (1).
242312121113 is an equidigital number, since it uses as much as digits as its factorization.
242312121113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 23.
Adding to 242312121113 its reverse (311121213242), we get a palindrome (553433334355).
The spelling of 242312121113 in words is "two hundred forty-two billion, three hundred twelve million, one hundred twenty-one thousand, one hundred thirteen".
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