Base | Representation |
---|---|
bin | 110111000111100011001001… |
… | …111001001100011111101010 |
3 | 1011210022022001011211002220012 |
4 | 313013203021321030133222 |
5 | 223233131411344300132 |
6 | 2215322122144331522 |
7 | 102026433010161563 |
oct | 6707431171143752 |
9 | 1153268034732805 |
10 | 242411341400042 |
11 | 7027008862a291 |
12 | 23230b37913ba2 |
13 | a5353a32b8329 |
14 | 43c0ab30d116a |
15 | 1d05a1e1ac0b2 |
hex | dc78c9e4c7ea |
242411341400042 has 8 divisors (see below), whose sum is σ = 363617728511076. Its totient is φ = 121205431896352.
The previous prime is 242411341400009. The next prime is 242411341400057. The reversal of 242411341400042 is 240004143114242.
It can be written as a sum of positive squares in 2 ways, for example, as 225530081840281 + 16881259559761 = 15017659^2 + 4108681^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 242411341399981 and 242411341400008.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118130243 + ... + 120164790.
Almost surely, 2242411341400042 is an apocalyptic number.
242411341400042 is a deficient number, since it is larger than the sum of its proper divisors (121206387111034).
242411341400042 is a wasteful number, since it uses less digits than its factorization.
242411341400042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 238803672.
The product of its (nonzero) digits is 24576, while the sum is 32.
Adding to 242411341400042 its reverse (240004143114242), we get a palindrome (482415484514284).
The spelling of 242411341400042 in words is "two hundred forty-two trillion, four hundred eleven billion, three hundred forty-one million, four hundred thousand, forty-two".
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