Search a number
-
+
243000141 = 381000047
BaseRepresentation
bin11100111101111…
…10001101001101
3121221020200112020
432132332031031
5444202001031
640040200353
76010316136
oct1636761515
9557220466
10243000141
1111519266a
12694690b9
133b461587
14243b6c8d
1516500096
hexe7be34d

243000141 has 4 divisors (see below), whose sum is σ = 324000192. Its totient is φ = 162000092.

The previous prime is 243000067. The next prime is 243000151. The reversal of 243000141 is 141000342.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 243000141 - 213 = 242991949 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 243000141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243000151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40500021 + ... + 40500026.

It is an arithmetic number, because the mean of its divisors is an integer number (81000048).

Almost surely, 2243000141 is an apocalyptic number.

It is an amenable number.

243000141 is a deficient number, since it is larger than the sum of its proper divisors (81000051).

243000141 is an equidigital number, since it uses as much as digits as its factorization.

243000141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81000050.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 243000141 is about 15588.4617906963. The cubic root of 243000141 is about 624.0252676118.

Adding to 243000141 its reverse (141000342), we get a palindrome (384000483).

The spelling of 243000141 in words is "two hundred forty-three million, one hundred forty-one", and thus it is an aban number.

Divisors: 1 3 81000047 243000141