Base | Representation |
---|---|
bin | 100011010111000111111… |
… | …101111100001000110111 |
3 | 22121022021200012120221120 |
4 | 203113013331330020313 |
5 | 304303130411102320 |
6 | 5100155402115023 |
7 | 340363643211654 |
oct | 43270775741067 |
9 | 8538250176846 |
10 | 2430011425335 |
11 | 85762011023a |
12 | 332b51aaba73 |
13 | 1481c2738050 |
14 | 858827d2c2b |
15 | 4332450a440 |
hex | 235c7f7c237 |
2430011425335 has 32 divisors (see below), whose sum is σ = 4197042349248. Its totient is φ = 1193471677440.
The previous prime is 2430011425327. The next prime is 2430011425349. The reversal of 2430011425335 is 5335241100342.
It is not a de Polignac number, because 2430011425335 - 23 = 2430011425327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2430011425296 and 2430011425305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14717902 + ... + 14882091.
It is an arithmetic number, because the mean of its divisors is an integer number (131157573414).
Almost surely, 22430011425335 is an apocalyptic number.
2430011425335 is a deficient number, since it is larger than the sum of its proper divisors (1767030923913).
2430011425335 is a wasteful number, since it uses less digits than its factorization.
2430011425335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29600435.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 2430011425335 its reverse (5335241100342), we get a palindrome (7765252525677).
The spelling of 2430011425335 in words is "two trillion, four hundred thirty billion, eleven million, four hundred twenty-five thousand, three hundred thirty-five".
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