Base | Representation |
---|---|
bin | 110111010000100100101010… |
… | …001000100100001010110110 |
3 | 1011212111120121022102110211012 |
4 | 313100210222020210022312 |
5 | 223323311332410120114 |
6 | 2220515033115512222 |
7 | 102122304266505425 |
oct | 6720445210441266 |
9 | 1155446538373735 |
10 | 243031431332534 |
11 | 7048a062197479 |
12 | 23311152758672 |
13 | a57b9c514a750 |
14 | 4402ad958b2bc |
15 | 1d16c12b0c63e |
hex | dd092a2242b6 |
243031431332534 has 16 divisors (see below), whose sum is σ = 392592970457520. Its totient is φ = 112167285714720.
The previous prime is 243031431332497. The next prime is 243031431332629. The reversal of 243031431332534 is 435233134130342.
It is a super-2 number, since 2×2430314313325342 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243031431332491 and 243031431332500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41678432 + ... + 47150339.
It is an arithmetic number, because the mean of its divisors is an integer number (24537060653595).
Almost surely, 2243031431332534 is an apocalyptic number.
243031431332534 is a deficient number, since it is larger than the sum of its proper divisors (149561539124986).
243031431332534 is a wasteful number, since it uses less digits than its factorization.
243031431332534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88934015.
The product of its (nonzero) digits is 933120, while the sum is 41.
Adding to 243031431332534 its reverse (435233134130342), we get a palindrome (678264565462876).
The spelling of 243031431332534 in words is "two hundred forty-three trillion, thirty-one billion, four hundred thirty-one million, three hundred thirty-two thousand, five hundred thirty-four".
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