Base | Representation |
---|---|
bin | 1110001001011010001… |
… | …1010100111111110001 |
3 | 212020100011012001110201 |
4 | 3202112203110333301 |
5 | 12440223231341032 |
6 | 303353004355201 |
7 | 23362600005262 |
oct | 3422643247761 |
9 | 766304161421 |
10 | 243044012017 |
11 | 94090010554 |
12 | 3b12ab45b01 |
13 | 19bc3c25981 |
14 | ba98a70969 |
15 | 64c72e58e7 |
hex | 38968d4ff1 |
243044012017 has 2 divisors, whose sum is σ = 243044012018. Its totient is φ = 243044012016.
The previous prime is 243044011981. The next prime is 243044012041. The reversal of 243044012017 is 710210440342.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 240697190881 + 2346821136 = 490609^2 + 48444^2 .
It is a cyclic number.
It is not a de Polignac number, because 243044012017 - 211 = 243044009969 is a prime.
It is not a weakly prime, because it can be changed into another prime (243044012077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121522006008 + 121522006009.
It is an arithmetic number, because the mean of its divisors is an integer number (121522006009).
Almost surely, 2243044012017 is an apocalyptic number.
It is an amenable number.
243044012017 is a deficient number, since it is larger than the sum of its proper divisors (1).
243044012017 is an equidigital number, since it uses as much as digits as its factorization.
243044012017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 28.
Adding to 243044012017 its reverse (710210440342), we get a palindrome (953254452359).
The spelling of 243044012017 in words is "two hundred forty-three billion, forty-four million, twelve thousand, seventeen".
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