Base | Representation |
---|---|
bin | 1110001001101000010… |
… | …0110111011010101011 |
3 | 212020111021102211111202 |
4 | 3202122010313122223 |
5 | 12440333400313103 |
6 | 303402515514415 |
7 | 23364215361542 |
oct | 3423204673253 |
9 | 766437384452 |
10 | 243103135403 |
11 | 94110422857 |
12 | 3b1468b8a0b |
13 | 19c0325691b |
14 | baa2861159 |
15 | 64cc5c3988 |
hex | 389a1376ab |
243103135403 has 2 divisors, whose sum is σ = 243103135404. Its totient is φ = 243103135402.
The previous prime is 243103135369. The next prime is 243103135411. The reversal of 243103135403 is 304531301342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243103135403 - 226 = 243036026539 is a prime.
It is not a weakly prime, because it can be changed into another prime (243103138403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121551567701 + 121551567702.
It is an arithmetic number, because the mean of its divisors is an integer number (121551567702).
Almost surely, 2243103135403 is an apocalyptic number.
243103135403 is a deficient number, since it is larger than the sum of its proper divisors (1).
243103135403 is an equidigital number, since it uses as much as digits as its factorization.
243103135403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 243103135403 its reverse (304531301342), we get a palindrome (547634436745).
The spelling of 243103135403 in words is "two hundred forty-three billion, one hundred three million, one hundred thirty-five thousand, four hundred three".
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