Base | Representation |
---|---|
bin | 1110001001101010111… |
… | …0110011101010001001 |
3 | 212020112001010102100011 |
4 | 3202122232303222021 |
5 | 12440344204130212 |
6 | 303403551311521 |
7 | 23364411003121 |
oct | 3423256635211 |
9 | 766461112304 |
10 | 243114130057 |
11 | 94116652247 |
12 | 3b14a51b5a1 |
13 | 19c05606136 |
14 | baa40c3c81 |
15 | 64cd5464a7 |
hex | 389abb3a89 |
243114130057 has 2 divisors, whose sum is σ = 243114130058. Its totient is φ = 243114130056.
The previous prime is 243114130003. The next prime is 243114130099. The reversal of 243114130057 is 750031411342.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 238382203536 + 4731926521 = 488244^2 + 68789^2 .
It is a cyclic number.
It is not a de Polignac number, because 243114130057 - 223 = 243105741449 is a prime.
It is not a weakly prime, because it can be changed into another prime (243114130157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121557065028 + 121557065029.
It is an arithmetic number, because the mean of its divisors is an integer number (121557065029).
Almost surely, 2243114130057 is an apocalyptic number.
It is an amenable number.
243114130057 is a deficient number, since it is larger than the sum of its proper divisors (1).
243114130057 is an equidigital number, since it uses as much as digits as its factorization.
243114130057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 243114130057 its reverse (750031411342), we get a palindrome (993145541399).
The spelling of 243114130057 in words is "two hundred forty-three billion, one hundred fourteen million, one hundred thirty thousand, fifty-seven".
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