Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1011010010101100111 |
3 | 212020112112020202002220 |
4 | 3202123021122111213 |
5 | 12440403000313411 |
6 | 303404401003423 |
7 | 23364524201025 |
oct | 3423311322547 |
9 | 766475222086 |
10 | 243121104231 |
11 | 9411a586025 |
12 | 3b150923573 |
13 | 19c06ba8675 |
14 | baa4dbb715 |
15 | 64cde72b06 |
hex | 389b25a567 |
243121104231 has 4 divisors (see below), whose sum is σ = 324161472312. Its totient is φ = 162080736152.
The previous prime is 243121104221. The next prime is 243121104299. The reversal of 243121104231 is 132401121342.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 243121104231 - 26 = 243121104167 is a prime.
It is a super-2 number, since 2×2431211042312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243121104221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40520184036 + ... + 40520184041.
It is an arithmetic number, because the mean of its divisors is an integer number (81040368078).
Almost surely, 2243121104231 is an apocalyptic number.
243121104231 is a deficient number, since it is larger than the sum of its proper divisors (81040368081).
243121104231 is an equidigital number, since it uses as much as digits as its factorization.
243121104231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81040368080.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 243121104231 its reverse (132401121342), we get a palindrome (375522225573).
The spelling of 243121104231 in words is "two hundred forty-three billion, one hundred twenty-one million, one hundred four thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •