Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1111110001011101011 |
3 | 212020112112112012111200 |
4 | 3202123021332023223 |
5 | 12440403020013201 |
6 | 303404404055243 |
7 | 23364525352050 |
oct | 3423311761353 |
9 | 766475465450 |
10 | 243121251051 |
11 | 9411a676368 |
12 | 3b150994523 |
13 | 19c06c2a443 |
14 | baa5019027 |
15 | 64cdea1386 |
hex | 389b27e2eb |
243121251051 has 96 divisors (see below), whose sum is σ = 422773198848. Its totient is φ = 131709473280.
The previous prime is 243121251047. The next prime is 243121251067. The reversal of 243121251051 is 150152121342.
It is a happy number.
243121251051 is a `hidden beast` number, since 2 + 431 + 2 + 125 + 105 + 1 = 666.
It is not a de Polignac number, because 243121251051 - 22 = 243121251047 is a prime.
It is not an unprimeable number, because it can be changed into a prime (243121251001) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 151288090 + ... + 151289696.
It is an arithmetic number, because the mean of its divisors is an integer number (4403887488).
Almost surely, 2243121251051 is an apocalyptic number.
243121251051 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
243121251051 is a deficient number, since it is larger than the sum of its proper divisors (179651947797).
243121251051 is a wasteful number, since it uses less digits than its factorization.
243121251051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3281 (or 3278 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 243121251051 its reverse (150152121342), we get a palindrome (393273372393).
The spelling of 243121251051 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred fifty-one thousand, fifty-one".
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