Base | Representation |
---|---|
bin | 10110101001000111… |
… | …011101010111111011 |
3 | 2022202100120202002001 |
4 | 112221013131113323 |
5 | 344242402010212 |
6 | 15100245321431 |
7 | 1520322535306 |
oct | 265107352773 |
9 | 68670522061 |
10 | 24312141307 |
11 | a34662a673 |
12 | 4866106277 |
13 | 23a5b8853c |
14 | 1268c8db3d |
15 | 9745ec657 |
hex | 5a91dd5fb |
24312141307 has 2 divisors, whose sum is σ = 24312141308. Its totient is φ = 24312141306.
The previous prime is 24312141289. The next prime is 24312141311. The reversal of 24312141307 is 70314121342.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-24312141307 is a prime.
It is not a weakly prime, because it can be changed into another prime (24312141317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12156070653 + 12156070654.
It is an arithmetic number, because the mean of its divisors is an integer number (12156070654).
Almost surely, 224312141307 is an apocalyptic number.
24312141307 is a deficient number, since it is larger than the sum of its proper divisors (1).
24312141307 is an equidigital number, since it uses as much as digits as its factorization.
24312141307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 24312141307 its reverse (70314121342), we get a palindrome (94626262649).
The spelling of 24312141307 in words is "twenty-four billion, three hundred twelve million, one hundred forty-one thousand, three hundred seven".
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