Base | Representation |
---|---|
bin | 1110001001101110101… |
… | …1101111100011110011 |
3 | 212020120011011222112120 |
4 | 3202123223233203303 |
5 | 12440412301312201 |
6 | 303405321525323 |
7 | 23364663533412 |
oct | 3423353574363 |
9 | 766504158476 |
10 | 243130104051 |
11 | 9412467279a |
12 | 3b153943843 |
13 | 19c08a09bc3 |
14 | baa6281479 |
15 | 64ceb4e536 |
hex | 389baef8f3 |
243130104051 has 4 divisors (see below), whose sum is σ = 324173472072. Its totient is φ = 162086736032.
The previous prime is 243130104013. The next prime is 243130104079. The reversal of 243130104051 is 150401031342.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-243130104051 is a prime.
It is a super-2 number, since 2×2431301040512 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (243130104251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40521684006 + ... + 40521684011.
It is an arithmetic number, because the mean of its divisors is an integer number (81043368018).
Almost surely, 2243130104051 is an apocalyptic number.
243130104051 is a deficient number, since it is larger than the sum of its proper divisors (81043368021).
243130104051 is an equidigital number, since it uses as much as digits as its factorization.
243130104051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81043368020.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 243130104051 its reverse (150401031342), we get a palindrome (393531135393).
The spelling of 243130104051 in words is "two hundred forty-three billion, one hundred thirty million, one hundred four thousand, fifty-one".
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