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243130135245611 is a prime number
BaseRepresentation
bin110111010010000000100101…
…010110000111001100101011
31011212212000101011020210001112
4313102000211112013030223
5223331421004110324421
62221032235303140535
7102132400255102025
oct6722004526071453
91155760334223045
10243130135245611
1170517a02a58259
12233282ba44474b
13a5880c5292343
1444077c0429015
151d1958d17b45b
hexdd202558732b

243130135245611 has 2 divisors, whose sum is σ = 243130135245612. Its totient is φ = 243130135245610.

The previous prime is 243130135245553. The next prime is 243130135245629. The reversal of 243130135245611 is 116542531031342.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 243130135245611 - 234 = 243112955376427 is a prime.

It is a super-2 number, since 2×2431301352456112 (a number of 30 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (243130135245671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565067622805 + 121565067622806.

It is an arithmetic number, because the mean of its divisors is an integer number (121565067622806).

Almost surely, 2243130135245611 is an apocalyptic number.

243130135245611 is a deficient number, since it is larger than the sum of its proper divisors (1).

243130135245611 is an equidigital number, since it uses as much as digits as its factorization.

243130135245611 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 41.

Adding to 243130135245611 its reverse (116542531031342), we get a palindrome (359672666276953).

The spelling of 243130135245611 in words is "two hundred forty-three trillion, one hundred thirty billion, one hundred thirty-five million, two hundred forty-five thousand, six hundred eleven".