Base | Representation |
---|---|
bin | 110111010010000001100001… |
… | …011110010000000111000011 |
3 | 1011212212002222110102102201001 |
4 | 313102001201132100013003 |
5 | 223331430040331342402 |
6 | 2221032523340352431 |
7 | 102132434254344412 |
oct | 6722014136200703 |
9 | 1155762873372631 |
10 | 243131144012227 |
11 | 70518380419579 |
12 | 23328540245717 |
13 | a58822627b873 |
14 | 44078783b9479 |
15 | 1d195eb9e0187 |
hex | dd20617901c3 |
243131144012227 has 2 divisors, whose sum is σ = 243131144012228. Its totient is φ = 243131144012226.
The previous prime is 243131144012213. The next prime is 243131144012261. The reversal of 243131144012227 is 722210441131342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 243131144012227 - 223 = 243131135623619 is a prime.
It is a super-2 number, since 2×2431311440122272 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (243131144012527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565572006113 + 121565572006114.
It is an arithmetic number, because the mean of its divisors is an integer number (121565572006114).
Almost surely, 2243131144012227 is an apocalyptic number.
243131144012227 is a deficient number, since it is larger than the sum of its proper divisors (1).
243131144012227 is an equidigital number, since it uses as much as digits as its factorization.
243131144012227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 37.
Adding to 243131144012227 its reverse (722210441131342), we get a palindrome (965341585143569).
The spelling of 243131144012227 in words is "two hundred forty-three trillion, one hundred thirty-one billion, one hundred forty-four million, twelve thousand, two hundred twenty-seven".
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