243132340133 has 4 divisors (see below), whose sum is σ = 243135466668. Its totient is φ = 243129213600.

The previous prime is 243132340109. The next prime is 243132340151. The reversal of 243132340133 is 331043231342.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 331043231342 = 2 ⋅165521615671.

It can be written as a sum of positive squares in 2 ways, for example, as 65872815649 + 177259524484 = 256657^2 + 421022^2 .

It is a cyclic number.

It is not a de Polignac number, because 243132340133 - 2¹² = 243132336037 is a prime.

It is a super-2 number, since 2×243132340133² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243132340096 and 243132340105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243132340163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1443566 + ... + 1603167.

It is an arithmetic number, because the mean of its divisors is an integer number (60783866667).

Almost surely, 2^243132340133 is an apocalyptic number.

It is an amenable number.

243132340133 is a deficient number, since it is larger than the sum of its proper divisors (3126535).

243132340133 is an equidigital number, since it uses as much as digits as its factorization.

243132340133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3126534.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 243132340133 its reverse (331043231342), we get a palindrome (574175571475).

The spelling of 243132340133 in words is "two hundred forty-three billion, one hundred thirty-two million, three hundred forty thousand, one hundred thirty-three".