243135444002141 has 4 divisors (see below), whose sum is σ = 243135489364032. Its totient is φ = 243135398640252.

The previous prime is 243135444002123. The next prime is 243135444002147. The reversal of 243135444002141 is 141200444531342.

243135444002141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 243135444002141 - 2³⁸ = 242860566095197 is a prime.

It is a super-2 number, since 2×243135444002141² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243135444002095 and 243135444002104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243135444002147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13365845 + ... + 25785978.

It is an arithmetic number, because the mean of its divisors is an integer number (60783872341008).

Almost surely, 2^{243135444002141} is an apocalyptic number.

It is an amenable number.

243135444002141 is a deficient number, since it is larger than the sum of its proper divisors (45361891).

243135444002141 is an equidigital number, since it uses as much as digits as its factorization.

243135444002141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45361890.

The product of its (nonzero) digits is 184320, while the sum is 38.

Adding to 243135444002141 its reverse (141200444531342), we get a palindrome (384335888533483).

The spelling of 243135444002141 in words is "two hundred forty-three trillion, one hundred thirty-five billion, four hundred forty-four million, two thousand, one hundred forty-one".