Base | Representation |
---|---|
bin | 110111010010001001111101… |
… | …110111111100001110000011 |
3 | 1011212212222101022111211210112 |
4 | 313102021331313330032003 |
5 | 223332102122333140024 |
6 | 2221041023133421535 |
7 | 102133205034625532 |
oct | 6722117567741603 |
9 | 1155788338454715 |
10 | 243140210443139 |
11 | 70521203163289 |
12 | 2332a25063a8ab |
13 | a58903c71ac99 |
14 | 4408098564319 |
15 | 1d1997c94000e |
hex | dd227ddfc383 |
243140210443139 has 2 divisors, whose sum is σ = 243140210443140. Its totient is φ = 243140210443138.
The previous prime is 243140210443129. The next prime is 243140210443189. The reversal of 243140210443139 is 931344012041342.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-243140210443139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 243140210443096 and 243140210443105.
It is not a weakly prime, because it can be changed into another prime (243140210443129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121570105221569 + 121570105221570.
It is an arithmetic number, because the mean of its divisors is an integer number (121570105221570).
Almost surely, 2243140210443139 is an apocalyptic number.
243140210443139 is a deficient number, since it is larger than the sum of its proper divisors (1).
243140210443139 is an equidigital number, since it uses as much as digits as its factorization.
243140210443139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 41.
The spelling of 243140210443139 in words is "two hundred forty-three trillion, one hundred forty billion, two hundred ten million, four hundred forty-three thousand, one hundred thirty-nine".
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