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243155055131 is a prime number
BaseRepresentation
bin1110001001110100101…
…0111011001000011011
3212020121220010121222122
43202131022323020123
512440440143231011
6303412012411455
723365415603162
oct3423512731033
9766556117878
10243155055131
119413776491a
123b160176b8b
1319c10c34a61
14baa96d83d9
1564d1e2c3db
hex389d2bb21b

243155055131 has 2 divisors, whose sum is σ = 243155055132. Its totient is φ = 243155055130.

The previous prime is 243155055113. The next prime is 243155055193. The reversal of 243155055131 is 131550551342.

Together with previous prime (243155055113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 243155055131 - 226 = 243087946267 is a prime.

It is a super-2 number, since 2×2431550551312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 243155055091 and 243155055100.

It is not a weakly prime, because it can be changed into another prime (243155055331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121577527565 + 121577527566.

It is an arithmetic number, because the mean of its divisors is an integer number (121577527566).

Almost surely, 2243155055131 is an apocalyptic number.

243155055131 is a deficient number, since it is larger than the sum of its proper divisors (1).

243155055131 is an equidigital number, since it uses as much as digits as its factorization.

243155055131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45000, while the sum is 35.

The spelling of 243155055131 in words is "two hundred forty-three billion, one hundred fifty-five million, fifty-five thousand, one hundred thirty-one".