Base | Representation |
---|---|
bin | 100011011010110101110… |
… | …010100010000000100011 |
3 | 22121200120202001220212022 |
4 | 203122311302202000203 |
5 | 304334313330142011 |
6 | 5102055333252055 |
7 | 340564552432352 |
oct | 43326562420043 |
9 | 8550522056768 |
10 | 2434001412131 |
11 | 859288385393 |
12 | 33388619402b |
13 | 1486aa261b93 |
14 | 85b4069b999 |
15 | 434a99538db |
hex | 236b5ca2023 |
2434001412131 has 2 divisors, whose sum is σ = 2434001412132. Its totient is φ = 2434001412130.
The previous prime is 2434001412127. The next prime is 2434001412149. The reversal of 2434001412131 is 1312141004342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2434001412131 - 22 = 2434001412127 is a prime.
It is a super-2 number, since 2×24340014121312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2434001412131.
It is not a weakly prime, because it can be changed into another prime (2434001112131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1217000706065 + 1217000706066.
It is an arithmetic number, because the mean of its divisors is an integer number (1217000706066).
Almost surely, 22434001412131 is an apocalyptic number.
2434001412131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2434001412131 is an equidigital number, since it uses as much as digits as its factorization.
2434001412131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 2434001412131 its reverse (1312141004342), we get a palindrome (3746142416473).
The spelling of 2434001412131 in words is "two trillion, four hundred thirty-four billion, one million, four hundred twelve thousand, one hundred thirty-one".
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