Base | Representation |
---|---|
bin | 1011000100011010111001… |
… | …00001110110011101101011 |
3 | 10012011222201100021120110012 |
4 | 11202031130201312131223 |
5 | 11142301114300403024 |
6 | 123434054531442135 |
7 | 5061405641405411 |
oct | 542153441663553 |
9 | 105158640246405 |
10 | 24341132044139 |
11 | 783501a515509 |
12 | 2891583a5634b |
13 | 1077488680811 |
14 | 60218d38b2b1 |
15 | 2c327e59c50e |
hex | 16235c87676b |
24341132044139 has 2 divisors, whose sum is σ = 24341132044140. Its totient is φ = 24341132044138.
The previous prime is 24341132044127. The next prime is 24341132044153. The reversal of 24341132044139 is 93144023114342.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-24341132044139 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 24341132044096 and 24341132044105.
It is not a weakly prime, because it can be changed into another prime (24341132041139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12170566022069 + 12170566022070.
It is an arithmetic number, because the mean of its divisors is an integer number (12170566022070).
Almost surely, 224341132044139 is an apocalyptic number.
24341132044139 is a deficient number, since it is larger than the sum of its proper divisors (1).
24341132044139 is an equidigital number, since it uses as much as digits as its factorization.
24341132044139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 41.
The spelling of 24341132044139 in words is "twenty-four trillion, three hundred forty-one billion, one hundred thirty-two million, forty-four thousand, one hundred thirty-nine".
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