Base | Representation |
---|---|
bin | 100011011011001111111… |
… | …100110101010001011001 |
3 | 22121201201022221202101121 |
4 | 203123033330311101121 |
5 | 304341213210220324 |
6 | 5102211052445241 |
7 | 340611462203401 |
oct | 43331774652131 |
9 | 8551638852347 |
10 | 2434440320089 |
11 | 859493105438 |
12 | 333989179821 |
13 | 14874a176c2b |
14 | 85b82aad801 |
15 | 434d32505e4 |
hex | 236cff35459 |
2434440320089 has 2 divisors, whose sum is σ = 2434440320090. Its totient is φ = 2434440320088.
The previous prime is 2434440320083. The next prime is 2434440320129. The reversal of 2434440320089 is 9800230444342.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1685336222025 + 749104098064 = 1298205^2 + 865508^2 .
It is a cyclic number.
It is not a de Polignac number, because 2434440320089 - 211 = 2434440318041 is a prime.
It is not a weakly prime, because it can be changed into another prime (2434440320083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1217220160044 + 1217220160045.
It is an arithmetic number, because the mean of its divisors is an integer number (1217220160045).
Almost surely, 22434440320089 is an apocalyptic number.
It is an amenable number.
2434440320089 is a deficient number, since it is larger than the sum of its proper divisors (1).
2434440320089 is an equidigital number, since it uses as much as digits as its factorization.
2434440320089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 663552, while the sum is 43.
The spelling of 2434440320089 in words is "two trillion, four hundred thirty-four billion, four hundred forty million, three hundred twenty thousand, eighty-nine".
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