Base | Representation |
---|---|
bin | 1110001101000011001… |
… | …1110011100101010011 |
3 | 212022212021100000121212 |
4 | 3203100303303211103 |
5 | 12444223440111011 |
6 | 304034001410335 |
7 | 23426035522412 |
oct | 3432063634523 |
9 | 768767300555 |
10 | 244021410131 |
11 | 945417a7194 |
12 | 3b3623399ab |
13 | 1a01b57b355 |
14 | bb4c7b7479 |
15 | 653301008b |
hex | 38d0cf3953 |
244021410131 has 2 divisors, whose sum is σ = 244021410132. Its totient is φ = 244021410130.
The previous prime is 244021410119. The next prime is 244021410187. The reversal of 244021410131 is 131014120442.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-244021410131 is a prime.
It is a super-2 number, since 2×2440214101312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 244021410097 and 244021410106.
It is not a weakly prime, because it can be changed into another prime (244021460131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122010705065 + 122010705066.
It is an arithmetic number, because the mean of its divisors is an integer number (122010705066).
Almost surely, 2244021410131 is an apocalyptic number.
244021410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
244021410131 is an equidigital number, since it uses as much as digits as its factorization.
244021410131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 244021410131 its reverse (131014120442), we get a palindrome (375035530573).
The spelling of 244021410131 in words is "two hundred forty-four billion, twenty-one million, four hundred ten thousand, one hundred thirty-one".
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