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2441132140211 is a prime number
BaseRepresentation
bin100011100001011110110…
…100000110011010110011
322122100222200210102212022
4203201132310012122303
5304443414311441321
65105235101422055
7341236346554142
oct43413664063263
98570880712768
102441132140211
118613074a8996
1233513626a92b
13149275679acb
1486219727759
1543775991dab
hex2385ed066b3

2441132140211 has 2 divisors, whose sum is σ = 2441132140212. Its totient is φ = 2441132140210.

The previous prime is 2441132140159. The next prime is 2441132140219. The reversal of 2441132140211 is 1120412311442.

2441132140211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2441132140211 is a prime.

It is a super-2 number, since 2×24411321402112 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2441132140219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1220566070105 + 1220566070106.

It is an arithmetic number, because the mean of its divisors is an integer number (1220566070106).

Almost surely, 22441132140211 is an apocalyptic number.

2441132140211 is a deficient number, since it is larger than the sum of its proper divisors (1).

2441132140211 is an equidigital number, since it uses as much as digits as its factorization.

2441132140211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 2441132140211 its reverse (1120412311442), we get a palindrome (3561544451653).

The spelling of 2441132140211 in words is "two trillion, four hundred forty-one billion, one hundred thirty-two million, one hundred forty thousand, two hundred eleven".