Base | Representation |
---|---|
bin | 100011100001100100101… |
… | …011110110011111101101 |
3 | 22122101020120010210201121 |
4 | 203201210223312133231 |
5 | 304444120021004013 |
6 | 5105252540540541 |
7 | 341241654033634 |
oct | 43414453663755 |
9 | 8571216123647 |
10 | 2441230641133 |
11 | 861358066109 |
12 | 335163251751 |
13 | 14928cbb718b |
14 | 8622884851b |
15 | 4377e44c58d |
hex | 23864af67ed |
2441230641133 has 4 divisors (see below), whose sum is σ = 2451444995520. Its totient is φ = 2431016286748.
The previous prime is 2441230641131. The next prime is 2441230641139. The reversal of 2441230641133 is 3311460321442.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2441230641133 - 21 = 2441230641131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2441230641131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5107176835 + ... + 5107177312.
It is an arithmetic number, because the mean of its divisors is an integer number (612861248880).
Almost surely, 22441230641133 is an apocalyptic number.
It is an amenable number.
2441230641133 is a deficient number, since it is larger than the sum of its proper divisors (10214354387).
2441230641133 is a wasteful number, since it uses less digits than its factorization.
2441230641133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10214354386.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 2441230641133 its reverse (3311460321442), we get a palindrome (5752690962575).
The spelling of 2441230641133 in words is "two trillion, four hundred forty-one billion, two hundred thirty million, six hundred forty-one thousand, one hundred thirty-three".
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